Hodgson to make nine changes

England manager Roy Hodgson announced that he will make nine changes for his side's final World Cup game against Costa Rica. Photo by: Matt Dunham/AP

England manager Roy Hodgson announced that he will make nine changes for his side's final World Cup game against Costa Rica. Photo by: Matt Dunham/AP

Published Jun 23, 2014

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England manager Roy Hodgson announced that he will make nine changes for his side's final World Cup game against Costa Rica in Belo Horizonte on Tuesday.

Centre-back Gary Cahill and striker Daniel Sturridge will be the only survivors from Thursday's 2-1 loss to Uruguay, which effectively sealed England's elimination in the group phase.

“Well, Ben Foster will play in goal,” Hodgson told a pre-match press conference at the Estadio Mineirao.

“The right-back will be Phil Jones. Gary Cahill will play centre-half alongside Chris Smalling, and Luke Shaw will play left-back.

“In midfield we will have (James) Milner, (Frank) Lampard, (Jack) Wilshere, (Ross) Barkley and (Adam) Lallana, and Sturridge will play up front.”

Southampton left-back Shaw, 18, and 20-year-old Everton midfielder Barkley will be making their first starts of the tournament.

Hodgson had already announced that 36-year-old Lampard would captain the side, on what is expected to be his final England appearance, with regular skipper Steven Gerrard starting on the bench.

While there is nothing riding on the game for England, Costa Rica require a point from the game to secure top spot in Group D.

England team to play Costa Rica:

Ben Foster; Phil Jones, Gary Cahill, Chris Smalling, Luke Shaw; Frank Lampard (capt), Jack Wilshere; Adam Lallana, Ross Barkley, James Milner; Daniel Sturridge – AFP

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